After a sterling performance against the Cowboys, Champ Bailey is set to receive a conference honor.
The NFL informed the Broncos on Tuesday that Bailey will be named AFC Defensive Player of the Week for games played during Week 4 (Oct. 4-5).
This marks the first time that Bailey has received such an award in his six seasons with Denver. He was twice named NFC Defensive Player of the Week as a member of the Washington Redskins (Week 6 in 1999 and Week 4 in 2003).
Bailey had a season-high eight tackles, a game-high four passes defended and his first interception of 2009 in the 17-10 victory over the Cowboys. Those four pass breakups tied for the highest single-game total in the NFL this season.
A pair of Bailey’s pass breakups came at key times — the final plays of the game, halting Dallas on third- and fourth-and-goal from the Denver 2-yard line to preserve the Broncos victory. His interception also came at a crucial point in the first half, halting a Cowboys drive at the Denver 3-yard line.
Bailey is the first Bronco to receive an AFC Defensive Player of the Week honor since Elvis Dumervil did in Week 14 of the 2007 season. His selection makes him the 21st Bronco to receive the award since its initiation by the NFL during the 1984 season.